Problems of String pattern

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Java Program to find Repeated Characters of String:-

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class Test {

 public static void main(String... args) throws Exception {

       Scanner scanner = new Scanner(System.in);

       String str = scanner.nextLine();

       System.out.println(str);

       new Test().printDuplicateChar(str);

       scanner.close();

 }

 private void printDuplicateChar(String str){

       Map<Character, Integer> dataMap = new HashMap<>();

       char[] chars = str.toCharArray();

       for(Character ch : chars) {

              dataMap.put(ch, dataMap.containsKey(ch) ? dataMap.get(ch)+1 : 1);

       }     

       dataMap.entrySet().stream().forEach(map -> {

       if(map.getValue() > 1) {

       System.out.println("duplicate char :: "+map.getKey()+" occurence is "+map.getValue());

       }

  });

 }

}

In above code we saving the string into HashMap character as key and occurrence as integer, here we iterate the string store into the map and print all elemnt whose occurrence is more than 1, complexity of above code in O(N).

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Check whether a string is anagram:-

import java.util.Scanner;

public class Test {

 public static void main(String... args) throws Exception {

       Scanner scanner = new Scanner(System.in);

       String one = scanner.next();

       String two = scanner.next();

       System.out.println(new Test().checkAnagram(one, two));

       scanner.close();

 }    

 public boolean checkAnagram(String one, String two) {

       if(!(one.length() == two.length())) {

              return false;

       }

       char[] chArray =  one.toCharArray();

       for(char ch : chArray) {

              if(two.replace(ch+"", "").isEmpty()); {

                     return true;

              }

       }

       return false;

 }

}

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Print all substrings of a given string

import java.util.Scanner;

public class Test {

 public static void main(String... args) throws Exception {

       Scanner scanner = new Scanner(System.in);

       String one = scanner.next();

       new Test().printAllSubString(one);

       scanner.close();

 }

 private void printAllSubString(String one) {

       for (int i = 0; i < one.length(); i++) {

              for (int j = i; j <= one.length(); j++) {

                     if (i != j) {

                           System.out.println(one.substring(i, j));

                     }

              }

      }

 }
}